You don’t have to do much to impress your friends with easy to learn magic card trick. Hey, he is counting cards, hehe!
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You don’t have to do much to impress your friends with easy to learn magic card trick. Hey, he is counting cards, hehe!
Pretty simple trick. The ‘cutting’ of the card is a distraction since when you stack the deck back together you are effectively undoing the ‘random cutting’.
Your deck will ALWAYS look like this after the re-stacking (from the top):
9 cards – third marked crad – 15 cards – second marked card – 15 cards – first marked card – 10 cards
The spacing is chosen so that doing the repeated ‘up-down’ split will leave te three markled cards for last.
Yeah math!
here is what happens:
The whole cutting the piles is a ruse. When you put the ace on the first pile there are 10 cards and then an ace. You cut the 15 into two parts x and y. You place x on top of the ace and then put the second ace on top of the y. You cut the last 15 pile into two parts c and d. you put c on top of the “ace y” pile and the ace on top of the d. the remaining 9 cards go on top of the “ace d”.
The piles are as such at this point from left to right and listed top to bottom:
9 ace d
c ace y
x ace 10
assembly creates the following pile from top to bottom:
9 ace d c ace y x ace 10
since d c = 15 and x y = 15:
9 ace 15 ace 15 ace 10
move 4 from the top to the bottom:
5 ace 15 ace 15 ace 14
Then it getting annoying to track. The first pass of “up then down” removes every other card while reversing the stack. the stack goes from “5 ace 15 ace 15 ace 14″ to “7 ace 7 ace 7 ace 2″. The next pass reduces it to “1 ace 3 ace 3 ace 3″. Another pass reduces it to “1 ace 1 ace 1 ace”.
Now that is one *ucked trick!!!
Nicely done sir. Magic has been a hobby of mine for years and I’ve never seen this trick. Thanks for the post!
Once you have the deck set up, adding the nine to the first pile will make the first ace 10 cards deep. Then since you merely rearranged the cards, there are still 15 in between the first and second pile, making the other one the 26th card in, then another 15 making the last card 42 cards deep. Then if you keep dividing it in half, they keep showing up as the even numbers until they are the only ones left. I’m sure you actually know how this works, but yeah…
The piles are: 10 | 15 | 15 | 9
4 Cards are being removed from the deck (always from top of 9 pile)
so the piles are now: 10 | 15 | 15 | 5
since you pick up the deck in reverse order, the stack (from top to bottom) will look like:
5 card1 15 card2 15 card3 10 –48 cards
48 = 3*(2^4), you throw out half the cards 4 times (24 12 6 3) to remain with 3.
However, when you deal the cards face down (the “remaining” pile) you reverse the order. Therefore the first round removes all the odd cards (1,3,5…) the second round removes every other card starting from the last (48,44,40…), the third is every other from the start again (2,10,18…) and reverse for the fourth.
This leaves cards 6,22,38… so the setup is just a fancy way of arranging the cards for the “trick”.
It prolly has to do with the uneven Piles. Because you start with a 10 and turn it to 11, and finish with a 9, the two 15s get cut and turn into even piles and odd piles, something about the binary order of the shuffling turns makes sure you never get the 3 cards they chose.
Now, that’s an amazing trick. Thanks for sharing!